安卓无法转换java类型的值。双到字符串

Question

我已经尝试了许多解决方案，这段代码在早上为我工作，现在当我运行它时，它显示了一个未知的错误，这是我的用户类 我甚至试着把它转换成doubl也没用。请帮助我

    public class createuser {

    public String getName() {
    return name;
    }

    public void setName(String name) {
    this.name = name;
    }

    public String getEmail() {
    return email;
    }

    public void setEmail(String email) {
    this.email = email;
    }

    public String getPassword() {
    return password;
    }

    public void setPassword(String password) {
    this.password = password;
    }

    public String getCode() {
    return code;
    }

    public void setCode(String code) {
    this.code = code;
    }

    public String getIssharing() {
    return issharing;
    }

    public void setIssharing(String issharing) {
    this.issharing = issharing;
    }

    public String getLat() {
    return lat;
    }

    public void setLat(String lat) {
    this.lat = lat;
    }

    public String getLng() {
    return lng;
    }

    public void setLng(String lng) {
    this.lng = lng;
    }

    public String getImgurl() {
    return imgurl;
    }

    public void setImgurl(String imgurl) {
    this.imgurl = imgurl;
    }

    public String getUserid() {
    return userid;
    }

    public void setUserid(String userid) {
    this.userid = userid;
    }

    public createuser() {
    }

    public String name, email, password, code, issharing, lat, lng, 
    imgurl, userid;

    public createuser(String name, String email, String password, String 
    code, String issharing, String lat, String lng, String imgurl, String 
    userid) {
    this.name = name;
    this.email = email;
    this.password = password;
    this.code = code;
    this.issharing = issharing;
    this.lat = lat;
    this.lng = lng;
    this.imgurl = imgurl;
    this.userid = userid;

    }
    }

这是我的运行时类

    code = (EditText)findViewById(R.id.editText);
    submit = (Button)findViewById(R.id.button);
    firebaseDatabase = FirebaseDatabase.getInstance();
    auth = FirebaseAuth.getInstance();
    user = auth.getCurrentUser();
    reference = 
          firebaseDatabase.getInstance().getReference().child("users");
    currentreference = 
          firebaseDatabase.getInstance().getReference().child("users")
                      .child(user.getUid());


          current_user_id = user.getUid();

     submit.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            query = 
     reference.orderByChild("code").equalTo(code.getText().toString());
            query.addListenerForSingleValueEvent
            (new ValueEventListener() {
                @Override
                public void onDataChange(@NonNull DataSnapshot 
     dataSnapshot) {
                    if (dataSnapshot.exists())
                    {


                        createuser createuser = null;

                        for (DataSnapshot childDss : 
      dataSnapshot.getChildren())
                        {
                            createuser = 
      childDss.getValue(createuser.class);
                            join_user_id = createuser.userid;

                            circlereference = 
      firebaseDatabase.getInstance().getReference().child("users")

      .child(join_user_id).child("Circlemembers");

                            circlejoin circlejoin = new 
       circlejoin(current_user_id);
                            circlejoin circlejoin1 = new 
        circlejoin(join_user_id);


        circlereference.child(user.getUid()).setValue(circlejoin)
                                    .addOnCompleteListener(new 
        OnCompleteListener<Void>() {
                                        @Override
                                        public void onComplete(@NonNull 
        Task<Void> task) {
                                            if (task.isSuccessful())
                                            {

        Toast.makeText(getApplicationContext(),"user joined 
        circle",Toast.LENGTH_SHORT).show();
                                                startActivity(new 
        Intent(joincircle.this,userlocation.class));
                                            }
                                        }
                                    });


                        }

                    }
                    else
                    {
                        Toast.makeText(getApplicationContext(),"circle 
          code is invalid",Toast.LENGTH_LONG).show();
                    }
                }

                @Override
                public void onCancelled(@NonNull DatabaseError 
         databaseError) {

                }
            });
          }
        });
       } 

实时数据库是这样的

    users
    NwKzgM0NhuY7gT7eFiN9nwzumMG2
       code: "7260232"
       email: "trackit385@gmail.com"
       imgurl: "na"
       issharing: "false"
       lat: 17.3932339
       lng: 78.4440638
       name: "tejesh"
       password: "kinglion"
       userid: "NwKzgM0NhuY7gT7eFiN9nwzumMG2"

任何人请帮助我我无法解决它我的错误是

    com.google.firebase.database.DatabaseException: Failed to convert 
     value of type java.lang.Double to String

Answer 1

您将得到以下错误：

com.google.firebase.database.DatabaseException: Failed to convert value of type java.lang.Double to String

因为createuser类中的lat和lng字段是String类型，而在数据库中，两个文件都有double值，这是不正确的。要解决这个问题，只需将类中字段的类型更改为double

公共类createuser{

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getCode() {
        return code;
    }

    public void setCode(String code) {
        this.code = code;
    }

    public String getIssharing() {
        return issharing;
    }

    public void setIssharing(String issharing) {
        this.issharing = issharing;
    }

    public double getLat() {
        return lat;
    }

    public void setLat(double lat) {
        this.lat = lat;
    }

    public double getLng() {
        return lng;
    }

    public void setLng(double lng) {
        this.lng = lng;
    }

    public String getImgurl() {
        return imgurl;
    }

    public void setImgurl(String imgurl) {
        this.imgurl = imgurl;
    }

    public String getUserid() {
        return userid;
    }

    public void setUserid(String userid) {
        this.userid = userid;
    }

    public createuser() {
    }

    public String name, email, password, code, issharing,
            imgurl, userid;
    public double lat, lng;

    public createuser(String name, String email, String password, String
            code, String issharing, double lat, double lng, String imgurl, String
                              userid) {
        this.name = name;
        this.email = email;
        this.password = password;
        this.code = code;
        this.issharing = issharing;
        this.lat = lat;
        this.lng = lng;
        this.imgurl = imgurl;
        this.userid = userid;

    }
}

Answer 2

我不知道，但是这个类缺少所有的字段声明。那应该是Double lat, Double lng。当字段为String且setter方法设置double时，这无法工作，至少除非添加匹配的setter。而且Double和double不是相同的数据类型。您将原语与复杂的数据类型（在这里，它们也有两种不同的蓝色）混淆，并且还定义了setter，但没有在构造函数中使用它们。。。第二种可能是口味的问题，但第一种在语法上是错误的，因为它意味着：按值调用与按引用调用。该类可能应该简单地称为User，因为您可能会在整个应用程序中使用它

public class User {

    private Double lat;
    private Double lng;
    ...

    public User() {}
    public User(String name, String email, String password, String code, String issharing, Double lat, Double lng, String imgurl, String userid) {
        ...
    }
    ...

    public Double getLat() { return this.lat; }
    public Double getLng() { return this.lng; }
    public void setLat(Double value) { this.lat = value; }
    public void setLng(Double value) { this.lng = value; } 

}